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fix potential deadlock bug in libc-internal locking logic
if a multithreaded program became non-multithreaded (i.e. all other threads exited) while one thread held an internal lock, the remaining thread would fail to release the lock. the the program then became multithreaded again at a later time, any further attempts to obtain the lock would deadlock permanently. the underlying cause is that the value of libc.threads_minus_1 at unlock time might not match the value at lock time. one solution would be returning a flag to the caller indicating whether the lock was taken and needs to be unlocked, but there is a simpler solution: using the lock itself as such a flag. note that this flag is not needed anyway for correctness; if the lock is not held, the unlock code is harmless. however, the memory synchronization properties associated with a_store are costly on some archs, so it's best to avoid executing the unlock code when it is unnecessary.
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@ -64,28 +64,27 @@ static struct {
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static inline void lock(volatile int *lk)
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{
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if (!libc.threads_minus_1) return;
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while(a_swap(lk, 1)) __wait(lk, lk+1, 1, 1);
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if (libc.threads_minus_1)
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while(a_swap(lk, 1)) __wait(lk, lk+1, 1, 1);
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}
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static inline void unlock(volatile int *lk)
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{
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if (!libc.threads_minus_1) return;
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a_store(lk, 0);
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if (lk[1]) __wake(lk, 1, 1);
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if (lk[0]) {
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a_store(lk, 0);
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if (lk[1]) __wake(lk, 1, 1);
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}
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}
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static inline void lock_bin(int i)
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{
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if (libc.threads_minus_1)
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lock(mal.bins[i].lock);
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lock(mal.bins[i].lock);
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if (!mal.bins[i].head)
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mal.bins[i].head = mal.bins[i].tail = BIN_TO_CHUNK(i);
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}
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static inline void unlock_bin(int i)
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{
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if (!libc.threads_minus_1) return;
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unlock(mal.bins[i].lock);
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}
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