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avoid function call to pthread_self in mutex unlock

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if the mutex was previously locked, we can assume pthread_self was
already called at the time of locking, and thus that the thread
pointer is initialized.
This commit is contained in:
Rich Felker
2011-03-17 13:35:08 -04:00
parent 93cc986ab3
commit 18c7ea8055
1 changed files with 1 additions and 1 deletions
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2
src/thread/pthread_mutex_unlock.c
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@ -3,7 +3,7 @@
int pthread_mutex_unlock(pthread_mutex_t *m) int pthread_mutex_unlock(pthread_mutex_t *m)
{ {
if (m->_m_type != PTHREAD_MUTEX_NORMAL) { if (m->_m_type != PTHREAD_MUTEX_NORMAL) {
if (m->_m_lock != pthread_self()->tid) if (!m->_m_lock || m->_m_lock != __pthread_self()->tid)
return EPERM; return EPERM;
if (m->_m_type == PTHREAD_MUTEX_RECURSIVE && --m->_m_count) if (m->_m_type == PTHREAD_MUTEX_RECURSIVE && --m->_m_count)
return 0; return 0;